Hi Jim, I just don't follow you there. Suppose you went into a shop that sold loose electrons. The guy at the till says, cheap ones over there, expensive ones there. He explains that the cheap ones are only to nine decimal places, your purchase could be plus or minus a few billion photon masses. Buy the cheap one, a photon rest mass is ludicrously small compared to an electron's mass.
We need to take the e.m. mass and balance it against grav mass. So first we'll look at the electron E = mc^2, that's
9.1093897E-31 * 8.98755178737E 16 = 8.18711116801E-14J
Now let's do the same for what I think is the speed of gravity
9.1093897E-31 *1.35639139448E 50 = 1.2355897798E 20J
So what's the e.m mass equivalent of the gravitational energy?
1.2355897798E 20 / c^2 = 1.37477903775E 03 That's over a tonne!!! But we only see one h / 2 of that energy in our e.m space. 4.55469484999E-31 half the electrons mass.
So, we've got to stash that, over a tonne, away inside of our electron. The obvious place to put it is inside the Schwartzchild radius. We need to work that out,
r = 2GM / c^2 = 1.35260912107E-57 metres. That's the top of our w shaped energy curve. It might be worth noting here that we have to keep in mind that that radius will be a lot smaller again for the speed of gravity, 8.96249015818E-91 metres.
Right, we did the sums to find out the balance state of the electron. All that peeks out from the centre of our w shaped energy profile is 6.03595039111E-64 kg. We still need to work out the radius of the e.m. electron. That's Lambda = h / mc
2.42631060001E-12 metres, the Compton wavelength.
In qm it will be stated that the electron, as point charge, is somewhere in that sphere of radius 2.42631060001E-12. I say that that is the actual e.m radius of the electron and the point will be the radius of 8.96249015818E-91 metres, where its grav mass lives. The thing is, that this electron is light years deep. It has a minute gravitational force at its e.m edge but its real mass is concentrated at a tiny point, which is ever so far away from the e.m. edge.
Now we need to look at this photon rest mass of 6.03595039111E-64 kg. What's its radius? Again, Lambda = h / mc = 3.66176117373E 21 metres!!! What's its Swartzchild radius? 8.96249015818E-91 same as for the electron, I'm sure it does differ but only when we get to thousands of decimal places.
We want to balance it, as we did for the electron, though we know that this rest mass is by definition not in balance, it has to go at the speed of light. We get 1.99973315029E-97 kg.
So how's the trick pulled off? An electron goes off like a tiny supernova and releases 6.03595039111E-64 kg of e.m energy, it also releases grav energy, equal to one electron mass.
6.03595039111E-64 *1.35639139448E 50 = 8.18711116801E-14 Then divide that by c^2 to get the e.m equivalent mass of an electron. The vacuum. which has a structure of its own, can construct from this information a photon anywhere it's needed within the radius of the photon.
That radius is huge, 3.66176117373E 21 metres.
That I believe is only part of the trick. Lets go back to what I'll call Newton's banking system. It's a natural log curve. The curve looks the same for both positive and negative values of x. When x equals zero, the curve snaps to a horizontal line of y equals one.
Okay, with this banking system, everything gets a bank statement instantaneously. So its not like our system of banking where true compound interest is being worked out but you get your statements monthly. We say, on this board, that the speed of gravity is not instantaneous. Go for 20 billion times c, or go for my value of 1.16464217444E 25 metres per second.
In the last post I looked at the potential energy balancing act in terms of x. When x gets very close to zero things start to get interesting. A photon can leap across the
x = zero value, because its bank statements are coming in instalments of h. It can hop back and forth playing the bull and bear markets for ever.
