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20 years 8 months ago #8629
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Jim</i>
<br />How can you tell the difference between the speed of light slowing and clocks slowing?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Speed has units of L/T, whereas time has units of just T. If f is the speed contraction factor, then L is contracted by sqrt(f), and T is expanded by sqrt(f), implying that speed L/T is slowed by [sqrt(f)]^2 = f. -|Tom|-
<br />How can you tell the difference between the speed of light slowing and clocks slowing?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Speed has units of L/T, whereas time has units of just T. If f is the speed contraction factor, then L is contracted by sqrt(f), and T is expanded by sqrt(f), implying that speed L/T is slowed by [sqrt(f)]^2 = f. -|Tom|-
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20 years 8 months ago #9325
by Jim
Replied by Jim on topic Reply from
How is that math any different than adding 2+2-2=2? Why do the extra math? The change in L is the same as the change in T if C is primary and constant. Then the atom will be constant too and better time can be maintained.
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20 years 8 months ago #8630
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Jim</i>
<br />The change in L is the same as the change in T if C is primary and constant. Then the atom will be constant too and better time can be maintained.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Length is contracted (made smaller); time intervals are dilated (made larger). These don't cancel in the ratio, they get bigger. -|Tom|-
<br />The change in L is the same as the change in T if C is primary and constant. Then the atom will be constant too and better time can be maintained.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Length is contracted (made smaller); time intervals are dilated (made larger). These don't cancel in the ratio, they get bigger. -|Tom|-
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20 years 8 months ago #8654
by Jim
Replied by Jim on topic Reply from
Using the posted equation in different ways still does not resolve redshift of the Hubble kind. If that redshift is caused by gravity as I suspect then some other equation is needed to resolve it. Can the idea that Hubble redshift is caused by the elysium(this stuff seems to be also known as IGM)explain the LAF? There is at least one other author saying this is so but he also says the IGM is much denser than is claimed in MM.
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20 years 8 months ago #8658
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Jim</i>
<br />Using the posted equation in different ways still does not resolve redshift of the Hubble kind. If that redshift is caused by gravity as I suspect then some other equation is needed to resolve it.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">I agree. Cosmological redshift is caused by friction of lightwaves with Le Sage-type gravitons. The fractional energy loss is proportional to distance traveled. That is a different equation.
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Can the idea that Hubble redshift is caused by the elysium(this stuff seems to be also known as IGM) explain the LAF? There is at least one other author saying this is so but he also says the IGM is much denser than is claimed in MM.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">No, elysium is unrelated to the intergalactic medium (IGM), and the density of elysium has never been specified. (It depends on elyson size, which is still unknown.)
What is "LAF"? -|Tom|-
<br />Using the posted equation in different ways still does not resolve redshift of the Hubble kind. If that redshift is caused by gravity as I suspect then some other equation is needed to resolve it.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">I agree. Cosmological redshift is caused by friction of lightwaves with Le Sage-type gravitons. The fractional energy loss is proportional to distance traveled. That is a different equation.
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Can the idea that Hubble redshift is caused by the elysium(this stuff seems to be also known as IGM) explain the LAF? There is at least one other author saying this is so but he also says the IGM is much denser than is claimed in MM.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">No, elysium is unrelated to the intergalactic medium (IGM), and the density of elysium has never been specified. (It depends on elyson size, which is still unknown.)
What is "LAF"? -|Tom|-
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20 years 8 months ago #9397
by Jim
Replied by Jim on topic Reply from
LAF is meant to mean the lyman alpha forest lines in quasar spectra.
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