Inelastic collisions of CGs

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20 years 10 months ago #7464 by tvanflandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by EBTX</i>
<br />What is the basic problem with elastic collisions? Why no net force? What was the gist of the argument?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">It was not obvious to my intuition, but it turns out that, for elastic collisions, the graviton shadow two bodies cast on one another is filled by backscattered gravitons that bounce off the other mass and newly enter the shadow. As Dicke explained the argument, if you have two perfectly reflective spheres bathed in a uniform light from all directions, they will each reflect as many photons toward the other as they block. So they will "disappear" in the uniform sea of light, rather than become visible via a dark shadow between them.

The full argument is made mathematically and rigorously by Slabinski in <i>Pushing Gravity</i>, who also presents the solution, solving the excess heat problem from absorbed gravitons in the process. -|Tom|-

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20 years 10 months ago #7696 by EBTX
Replied by EBTX on topic Reply from
Then, would it be inconsistent with your model to ever have the gravitons "emitted" by the MIs? That is, do you see CGs as possibly being absorbed completely by MIs?

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20 years 10 months ago #7290 by tvanflandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by EBTX</i>
<br />Then, would it be inconsistent with your model to ever have the gravitons "emitted" by the MIs? That is, do you see CGs as possibly being absorbed completely by MIs?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">I see no inconsistency. Indeed, I have proposed that radioactive decay and spontaneous photon emissions are "supernova" events on a quantum scale, and must eventually dump all absorbed gravitons back into the universal sea of gravitons. Otherwise, the universe would be losing gravitons and running down. -|Tom|-

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