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Deep-Gas, Deep Hot Biosphere Theory
17 years 3 months ago #18067
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
Having the two proton cones (or half spheres or etc..) joined at their tips - because they have shielded each other from the gravitation flux <b>in the direction of their asymmetric shape</b>, let's bring back in the elysons.
The elysons will pile up against the entire surface of the protons - assuming that Elysium can be compressed. When the cone proton is entirely exposed to the uniform gravitational flux, condensed elysons on the outer surface would flow from the tip of the cone to the base. Then they would be driven inward, etc.
But when the two protons are "attached" tip to tip, what happens? The condensed elysons would flow from the overall outer surface of each cone <b>to the tip to tip position.</b> Since the condensed elysons are constantly being "pressured" by the gravitons, they will form a liquid layer at and around the tip to tip position. <b>Now you have a chemical bond!</b> They would act as a glue or adhesive. Perceptually, this is a much better description of a chemical bond than proposing such a bond is made by electrons doing a square dance. And a dosy doh...
At a much larger scale, the convergence of elysons along with the convergence of protons would mutually reinforce one another's inward progression - brought on by the pressure of the gravitons. There are no attractive forces whatsoever. Everyone is simply getting in each other's way.
Since mainstream cosmology claims that this inward "collapse" raises the temperature - fine. I will agree with that. But the medium which really exhibits the temperature is the Elysium. Consider how you measure temperature: by the electromagnetic wavelength of the Elysium. The protons will have acquired higher velocity - but by virtue of their geometry interacting with the elysons and ultimately the gravitons.
Let's look next at nuclear fusion - what is it and how does it happen. Secret nuclear energies or forces are not needed.....
Gregg Wilson
The elysons will pile up against the entire surface of the protons - assuming that Elysium can be compressed. When the cone proton is entirely exposed to the uniform gravitational flux, condensed elysons on the outer surface would flow from the tip of the cone to the base. Then they would be driven inward, etc.
But when the two protons are "attached" tip to tip, what happens? The condensed elysons would flow from the overall outer surface of each cone <b>to the tip to tip position.</b> Since the condensed elysons are constantly being "pressured" by the gravitons, they will form a liquid layer at and around the tip to tip position. <b>Now you have a chemical bond!</b> They would act as a glue or adhesive. Perceptually, this is a much better description of a chemical bond than proposing such a bond is made by electrons doing a square dance. And a dosy doh...
At a much larger scale, the convergence of elysons along with the convergence of protons would mutually reinforce one another's inward progression - brought on by the pressure of the gravitons. There are no attractive forces whatsoever. Everyone is simply getting in each other's way.
Since mainstream cosmology claims that this inward "collapse" raises the temperature - fine. I will agree with that. But the medium which really exhibits the temperature is the Elysium. Consider how you measure temperature: by the electromagnetic wavelength of the Elysium. The protons will have acquired higher velocity - but by virtue of their geometry interacting with the elysons and ultimately the gravitons.
Let's look next at nuclear fusion - what is it and how does it happen. Secret nuclear energies or forces are not needed.....
Gregg Wilson
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- neilderosa
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17 years 3 months ago #19914
by neilderosa
Replied by neilderosa on topic Reply from Neil DeRosa
Gregg,
This meta-model type speculation on quantum physics (if that’s the right term), is quite intriguing. Although I understand what you are saying, I’m not qualified to comment on it, but I hope you will continue to develop your theory.
However I would be very interested in reactions from Tom or Larry, who are qualified to evaluate it in terms of meta-model physics.
Neil
This meta-model type speculation on quantum physics (if that’s the right term), is quite intriguing. Although I understand what you are saying, I’m not qualified to comment on it, but I hope you will continue to develop your theory.
However I would be very interested in reactions from Tom or Larry, who are qualified to evaluate it in terms of meta-model physics.
Neil
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- Larry Burford
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17 years 3 months ago #18075
by Larry Burford
Replied by Larry Burford on topic Reply from Larry Burford
Gregg,
I'm hopeing that your assymetrical particle model has evolved beyond a description of hydrogen in the last few years, but I see no sign of that in these last few posts. Helium? Lithium? Uranium?
Perhaps you pending fusion discussion moves in this direction.
LB
I'm hopeing that your assymetrical particle model has evolved beyond a description of hydrogen in the last few years, but I see no sign of that in these last few posts. Helium? Lithium? Uranium?
Perhaps you pending fusion discussion moves in this direction.
LB
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17 years 3 months ago #18068
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Larry Burford</i>
<br />Gregg,
I'm hopeing that your assymetrical particle model has evolved beyond a description of hydrogen in the last few years, but I see no sign of that in these last few posts. Helium? Lithium? Uranium?
Perhaps you pending fusion discussion moves in this direction.
LB
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Slowly but surely....
Looking at current results for fusion reactors, we see a rarified plasma confined by magnetic fields. The plasma consists of nuclei raised to such a high temperature, that their “Coulomb repulsive Field” cannot be distinguished from the rest of the Elysium. For our discussion, this means that the entire volume of Elysium is in a hot, vapor state. One would not find any locality around or on the proton which could be described as condensed or cool. Going over the actual results of these fusion reactor experiments, one does not find any <b>hard evidence</b> of nuclear fusion or net energy output. This <b>is</b> what would be predicted by asymmetric protons in these conditions.
What is missing in these nuclear fusion reactors? I propose it is a huge amount of Elysium. If we go back to a primordial nebula, let it have a substantial amount of elysons, in addition to protons. As the nebula contracts, a portion of the Elysium – assuming it is compressible – will contract to a liquid state. In time we would have a mass of protons within a mixture of liquid and vapor Elysium. Given a high temperature, we would assume a very high velocity for the protons.
But would that very high velocity actually be present in high density Elysium? I submit it would not. There will be, of course, countless collisions between protons – all of them random. Without there being any purpose or design to it – a few collisions will be proton base to proton base. In perhaps one out of a trillion collisions, the mutually opposing Elysium vapors coming out of each of the two proton bases would lead to a soft docking between the two protons. Too high a temperature, that is, proton velocity, would lead to a breaking apart. If there were a soft docking, what would happen? The trapped Elysium within the two protons would be very dense and very hot – but unorganized. And, this inside Elysium would not have gravitons. Outside the two, fused protons, the Elysium would be equally dense and hot – but the continuous, ongoing gravitational flux would also push on outside of the two protons. Checkmate.
I now propose that we have deuterium. Two fused protons are now two “neutrons”. Have always wondered who came up with the name “deuterium”. Inside joke?
There is no concave surface or low point on the deuterium where liquid Elysium would be cornered and vaporized. Therefore, there would be no “Electron”, no “Coulomb Force”, no “Charge”. And we are told that a neutron has no charge. I agree.
Next we can move on to larger nuclei....
Gregg Wilson
<br />Gregg,
I'm hopeing that your assymetrical particle model has evolved beyond a description of hydrogen in the last few years, but I see no sign of that in these last few posts. Helium? Lithium? Uranium?
Perhaps you pending fusion discussion moves in this direction.
LB
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Slowly but surely....
Looking at current results for fusion reactors, we see a rarified plasma confined by magnetic fields. The plasma consists of nuclei raised to such a high temperature, that their “Coulomb repulsive Field” cannot be distinguished from the rest of the Elysium. For our discussion, this means that the entire volume of Elysium is in a hot, vapor state. One would not find any locality around or on the proton which could be described as condensed or cool. Going over the actual results of these fusion reactor experiments, one does not find any <b>hard evidence</b> of nuclear fusion or net energy output. This <b>is</b> what would be predicted by asymmetric protons in these conditions.
What is missing in these nuclear fusion reactors? I propose it is a huge amount of Elysium. If we go back to a primordial nebula, let it have a substantial amount of elysons, in addition to protons. As the nebula contracts, a portion of the Elysium – assuming it is compressible – will contract to a liquid state. In time we would have a mass of protons within a mixture of liquid and vapor Elysium. Given a high temperature, we would assume a very high velocity for the protons.
But would that very high velocity actually be present in high density Elysium? I submit it would not. There will be, of course, countless collisions between protons – all of them random. Without there being any purpose or design to it – a few collisions will be proton base to proton base. In perhaps one out of a trillion collisions, the mutually opposing Elysium vapors coming out of each of the two proton bases would lead to a soft docking between the two protons. Too high a temperature, that is, proton velocity, would lead to a breaking apart. If there were a soft docking, what would happen? The trapped Elysium within the two protons would be very dense and very hot – but unorganized. And, this inside Elysium would not have gravitons. Outside the two, fused protons, the Elysium would be equally dense and hot – but the continuous, ongoing gravitational flux would also push on outside of the two protons. Checkmate.
I now propose that we have deuterium. Two fused protons are now two “neutrons”. Have always wondered who came up with the name “deuterium”. Inside joke?
There is no concave surface or low point on the deuterium where liquid Elysium would be cornered and vaporized. Therefore, there would be no “Electron”, no “Coulomb Force”, no “Charge”. And we are told that a neutron has no charge. I agree.
Next we can move on to larger nuclei....
Gregg Wilson
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17 years 3 months ago #18076
by Stoat
Replied by Stoat on topic Reply from Robert Turner
I think a rotating toroidal form might be able to do the trick. Grab arubber ring and twist it so that the inside toroidal radius is on the outside. Then do that at a great lick []
A model to see what it can do. Take a small electic motor and attach a spring to it. Twist that round to the back of the motor and stick it to a bearing. Then wrap the spring in a concertina like plastic sheet.Pull that back a bit at each end and seal it if need be. Then test it out in water or smoke. Two of them would be nice, they should chase each other, or be attracted to each other by the bernoulli effect.
A model to see what it can do. Take a small electic motor and attach a spring to it. Twist that round to the back of the motor and stick it to a bearing. Then wrap the spring in a concertina like plastic sheet.Pull that back a bit at each end and seal it if need be. Then test it out in water or smoke. Two of them would be nice, they should chase each other, or be attracted to each other by the bernoulli effect.
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17 years 3 months ago #18069
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />I think a rotating toroidal form might be able to do the trick. Grab arubber ring and twist it so that the inside toroidal radius is on the outside. Then do that at a great lick []
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I make it a practice to never lick my toroidal, but thanks for the input....
Gregg Wilson
<br />I think a rotating toroidal form might be able to do the trick. Grab arubber ring and twist it so that the inside toroidal radius is on the outside. Then do that at a great lick []
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I make it a practice to never lick my toroidal, but thanks for the input....
Gregg Wilson
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