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Stellar Splitting and pairing NEW Black holes foun
16 years 2 months ago #15436
by Jim
Replied by Jim on topic Reply from
Comic, The dynamics of a galaxy is not well modeled in that all of them misplace the gravity center at the mass center. So you can't use the galatic structure to prove the "speed of gravitrons". The reason the disk forms should be studied in light of the fact that every star in the structure is contributing to the force that forms the combined mass into a disk rather than an ever larger sphere.
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16 years 2 months ago #15437
by cosmicsurfer
Replied by cosmicsurfer on topic Reply from John Rickey
Not so Jim, You are using mass itself as the force which is wrong. Hurricanes circulate wind at extreme speeds around the eyewalls. Galaxies also circulate gravitons, and Mass is much like small vortical structures generated around the arms of galaxies as created by the GRAVITON CYCLE. Sorry but you really do not have a clue if you think mass is self generating motion. Core dynamics are reversed from antimatter induction taking place which generates both jets and a reverse motion antigraviton repulsive force around the galaxy that is why antimatter clouds move up against this boundary because they are being pushed by this force which is a physical particle that moves faster than light causing gravity to be an instantaneous equalizing force. John
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16 years 2 months ago #20957
by Jim
Replied by Jim on topic Reply from
Comic, So are you saying the stars in a galaxy do not have an effect on the disk structure? Is mass not real and every bit of mass has a property called gravity?
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16 years 2 months ago #15438
by cosmicsurfer
Replied by cosmicsurfer on topic Reply from John Rickey
Nope, gravitons create the stars and mass that circulates in the disk structure. Mass build up does cause drag, greater graviton capture, and greater antimatter induction to take place in the AGN---and the greater the mass being created the stronger the torque between the reverse motion core and event horizon [disk moves in opposite direction causing shearing forces] which will eventually result in quasar ejections from a dual fission process in antimatter core. Mass is created in hot creational zones from high levels of circulating gravitons and galaxy formations of mass circulation are the tail of a very large scale graviton stream which terminates at the eye wall of black holes in gravitons flipping polarity [becoming antigravitons when they fall through event horizon] into the antimatter core. The gravity field is caused by gravitons being captured by mass circulating as gravitomagnetic fields. John
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16 years 2 months ago #15439
by Stoat
Replied by Stoat on topic Reply from Robert Turner
Lets play another hunch. Well take a look at G =4pi*2GT / c^4 here G is curvature and T is some rather vague; to me at any rate; notion of materiality. The 4 pi bit is the surface of a sphere. So lets look at that in terms of our old friend
1- 1/eta^2 = 2GM / rc^2
Well take r to equal one, giving us a unit sphere and work out T.
That will give us an equation 4pi / c^2 - 4pi / c^2 *h^-1 = 8piGT / c^4 Tidy that up a bit 1 /c^2 - 1 / (c^2 *1.5091889611E 33) = 2piGT / c^4
I think that the c^4 should be rather the reciprocal of barh. Then well get some huge value for T but I suspect that that will be the reciprocal of a very small mass.
(Edited) I have to revise this. Ive got 2pi on the top line and barh on the bottom, so I can get rid of the 2pi and replace barh with h.
Ive said that I think that c^4 should be barh^-1
So change 1 /c^2 - 1 / (c^2 *1.5091889611E 33) = 2piGT / c^4 to
1 / (sqrt h^-1) - 1 / (sqrt h^1 * h^-1) =GT / h^-1
We get a huge value for T but its reciprocal is 1.717602369E-27
Thats 1.02547796279E 00 proton masses.
1- 1/eta^2 = 2GM / rc^2
Well take r to equal one, giving us a unit sphere and work out T.
That will give us an equation 4pi / c^2 - 4pi / c^2 *h^-1 = 8piGT / c^4 Tidy that up a bit 1 /c^2 - 1 / (c^2 *1.5091889611E 33) = 2piGT / c^4
I think that the c^4 should be rather the reciprocal of barh. Then well get some huge value for T but I suspect that that will be the reciprocal of a very small mass.
(Edited) I have to revise this. Ive got 2pi on the top line and barh on the bottom, so I can get rid of the 2pi and replace barh with h.
Ive said that I think that c^4 should be barh^-1
So change 1 /c^2 - 1 / (c^2 *1.5091889611E 33) = 2piGT / c^4 to
1 / (sqrt h^-1) - 1 / (sqrt h^1 * h^-1) =GT / h^-1
We get a huge value for T but its reciprocal is 1.717602369E-27
Thats 1.02547796279E 00 proton masses.
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16 years 2 months ago #20240
by Jim
Replied by Jim on topic Reply from
Can either of you math gus explain how Planck got the number for his constant from the laws that were in place when he did the deed? I never been able to get that number and wonder if anyone other than himself ever has. A good math guy must know how render his result from the stuff he used.
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