Gravitational Shielding

makis
Offline
Premium Member

22 years 2 weeks ago #3759 by makis

Replied by makis on topic Reply from

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>

what if our object is to instead create a region where no MI's exist

<hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

Doesn't it that imply some type of intelligent propagating or direction mechanism? If not, then the limitting solution is the singularity M=0, or an object without any mass at all, in which case the question of gravity is irrelevant anyway. Catch 22... <img src=icon_smile_cool.gif border=0 align=middle>

Please Log in or Create an account to join the conversation.

kevinvf
Offline
New Member

22 years 2 weeks ago #3434 by kevinvf

Replied by kevinvf on topic Reply from Kevin

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>1.A dense enough sphere will increase the force exerted by gravitons on earth but not the force exerted by gravitons on the sphere. This is due to virtually no graviton leaving the dense sphere, whereas the same amount of graviton density is leaving earth. <hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

I’m not sure I understand why the force exerted by gravitons on the Earth would increase. It seems like the sphere would in fact block gravitons en-route to the Earth from a given direction decreasing the force on the Earth.

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote> 2. The net result is that the earth will be pushed towards the sphere, an action similar to the sphere moving towards the earth <hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

Agreed, the net result is the same. The push towards the Earth is relative to the volume of gravitons that are allowed to pass through the sphere and vice versa.

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>3. The only way to shield gravity is to make a sphere that will absorb the same exactly flux of gravitons as earth does. It must be exactly the same, otherwise, motion of either the sphere towards the earth or the earth towards the sphere will occur.<hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

I see your point now. The area you are “shielding” is the area between the sphere and the earth. The problem as you state later is that you aren’t shielding gravity here your just neutralizing the effects of one mass with another creating a state of equilibrium between the two masses.

I had interpreted the idea of shielding gravity with a sphere as referring to items on the inside of the sphere as if the sphere were hollow. Not sure if that was a correct interpretation or not. Items inside a hollow sphere would be shielded from the effects of gravity outside the field. On the inside, it would depend on if gravitons were trapped inside, and how they would react in such a container. The guess would be items inside the sphere would be gravitationally susceptible only to each other.

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>4. It seems that Pushing Gravity theory generates a singularity for gravity shielding: M=0, i.e nothing to shield for. <hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>But if you are frustrated failing to either detect gravitons or shield gravity at all, what can I say then, just go after me..<img src=icon_smile_blackeye.gif border=0 align=middle> <hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

Hey Makis, it was meant in good humor. Hopefully it’s clear that my opinions are in no way a reflection of Meta research or Tom Van Flandern. I agree with you that any speculation on this or any other subject with a lack of the requisite empirical data falls in the realm of fiction. I would describe myself as “excited” about the possibilities, and less “frustrated” about the lack of progress. Being an engineer and not a scientist myself, I generally like to wait for the smart people to figure these things out so I can play and make toys with the results. Hopefully my input hasn’t randomized the purpose of your posts, mostly just fantasizing.

Kevin

Please Log in or Create an account to join the conversation.

makis
Offline
Premium Member

22 years 2 weeks ago #3374 by makis

Replied by makis on topic Reply from

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>

quote: from Makis

1.A dense enough sphere will increase the force exerted by gravitons on earth but not the force exerted by gravitons on the sphere. This is due to virtually no graviton leaving the dense sphere, whereas the same amount of graviton density is leaving earth.

I’m not sure I understand why the force exerted by gravitons on the Earth would increase. It seems like the sphere would in fact block gravitons en-route to the Earth from a given direction decreasing the force on the Earth.

<hr height=1 noshade id=quote></BLOCKQUOTE id=quote>

The gravity force (push)on an object in a two body system is the difference between the gravitons arriving from the free side(s) and those going through the object faced (dense sphere in this case). If the object faced blocks all gravitons, the gravity force is increased.

To understand this better you must reverse your mind frame from the traditional concept of a pulling gravity to pushing gravity.

>10 M1 ---->2 7<

M2 <

10

In the example above (simplified for illustration purposes), 10 gravitons hit masses M1 and M2. After absorption by M1, 2 gravitons emerge and hit M2. After absorption by M2, 7 gravitons emerge and hit M1.

Force on M1 = 10 - 7 = 3
Force on M2 = 10 - 2 = 8

Net Force = - 5 in the direction of M1, i.e. M2 is being pushed towards M1.

Now, if M2 is infinitely dense, then the following results:

>10 M1 ---->2 0<

M2 <

10

Force on M1 = 10 - 0 = 10
Force on M2 = 10 - 2 = 8

Net force = + 2, in the direction of M2, i.e. M1 is being pushed towards M2 (that does not mean M2 pulls M1, however)

To make M2 levitate, it must absorb equal amount of gravitons as M1:

>10 M1 ---->2 2<

M2 <

10

Force on M1 = 10 - 2 = 2
Force on M2 = 10 - 2 = 8

Net force = 0, i.e. no pushing (or pulling). M2 remains position wrt to M1.

To move M2 away from M1 we must generate a graviton burst as followes:

>B burst

>10 M1 ---->2 0<

M2 <

10

Force on M1 = 10 - 0 = 10
Force on M2 = 10 + B - 2 = 8 + B

Net force = B-2, in the direction of M2, i.e. M2 is being pushed away from M1, if B > 2.

DISCLAIMER: The above is based on my own opinions and is in no way a reflection of Meta research or Tom Van Flandern.

Please Log in or Create an account to join the conversation.

makis
Offline
Premium Member

22 years 2 weeks ago #3332 by makis

Replied by makis on topic Reply from

I corrected some errors on levitation and with the burst being generated after M1.

To make M2 levitate, it must absorb equal amount of gravitons as M1:

>10 M1 ---->2 2<

M2 <

10

Force on M1 = 10 - 2 = 8
Force on M2 = 10 - 2 = 8

Net force = 0, i.e. no pushing (or pulling). M2 remains position wrt to M1.

To move M2 away from M1 we must generate a graviton burst as followes:

>B burst

>10 M1 ---->2 0<

M2 <

10

Force on M1 = 10 - 0 = 10
Force on M2 = 10 + B - 2 = 8 + B

Net force = B-2, in the direction of M2, i.e. M2 is being pushed away from M1, if B > 2.

Please Log in or Create an account to join the conversation.

Quantum_Gravity
Offline
Premium Member

22 years 6 days ago #3502 by Quantum_Gravity

Replied by Quantum_Gravity on topic Reply from Randall damron

how many stages in the atmosphere would there be for a gravity equation model for an equation? what spots would be the points that gravity is multipied to get one more to it: _____1_____
so then second stage would have a graviton: 2 (n arrow pointing 1, 2 and keep goinf down)each satge would have to be second graviton level? I am questioning my own idea so please help! If i have the idea lets keep going.

The intuitive mind

Please Log in or Create an account to join the conversation.

Patrick
Offline
Premium Member

21 years 11 months ago #4342 by Patrick

Replied by Patrick on topic Reply from P

<BLOCKQUOTE id=quote>quote:<hr height=1 noshade id=quote>Doesn't it that imply some type of intelligent propagating or direction mechanism? If not, then the limitting solution is the singularity M=0, or an object without any mass at all, in which case the question of gravity is irrelevant anyway. Catch 22... <img src=icon_smile_cool.gif border=0 align=middle><hr height=1 noshade id=quote></BLOCKQUOTE id=quote>
Rather than trying to create a huge and highly dense object, what if you were able to place a sheet of "energy"(perhaps plasma) between the earth and the object, a sort of electronic force field/shield.

Since gravity is a product of mass and mass is a product of energy then wouldn't "energy" block the effects of the gravity more effectively?

Please Log in or Create an account to join the conversation.

Time to create page: 0.535 seconds