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Replication Theory:: Fractal Resonance
15 years 3 months ago #22968
by evolivid
Replied by evolivid on topic Reply from Mark Baker
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">
The fields are 1. Gravitomagnetic field, 2. Magnetic field, 3. Electric field/>>>electron motion is attached to G Field by a vortex. I think that there is a reverse motion positron that takes a discharge each time it passes electron [twice per rotation] taking extra heat from circuit and discharges it up through the antgraviton vortex. The exit wave is very cold and that is why high speed free energy motion using magnets results in antigraviton production (reverse time wave)---spinning magnets get very cold to touch. The gravitons circulate downwards around vertical axis forming the gravitomagnetic field which increases in horizontal size with increased rotation.
The exiting antigraviton creates the G-Force effect. It is repulsive to matter and high speed motion will hit this force field causing a buffeting effect and drag at high G motions. Rotating magnetic fields increase production of antigravitons creating lift and shielding against G-Forces. Let me know when you have your simulation up and working. John
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this starts to get interesting seeing the thermodynamic effects of the vortex .. it looks like there is a spinning magnet experiment in order.. and then thinking how a current could be viewed as a spinning magnet.. how fast would it have to spin to get cold .. is there math for this or do we need the experiment to derive the math...
but if the idea is right then it would lead to some new torque electric motors,that would be geared to move the magnet as well as the electromagnet in the middle of the magnet! that could be resonant with a fuel cell...
if the feul cell is viewed as the capacitor and the motor a inductor,
im working on the circuit for the motor because it is a raising inductance so I need to make a reactive circuit, but the fuel cell will make hydrogen and oxygen that could be put back together to make more energy in resonance with the motor using the same water over and over agian, the motor would be very efficient, maybe over-unity efficient
MARX
The fields are 1. Gravitomagnetic field, 2. Magnetic field, 3. Electric field/>>>electron motion is attached to G Field by a vortex. I think that there is a reverse motion positron that takes a discharge each time it passes electron [twice per rotation] taking extra heat from circuit and discharges it up through the antgraviton vortex. The exit wave is very cold and that is why high speed free energy motion using magnets results in antigraviton production (reverse time wave)---spinning magnets get very cold to touch. The gravitons circulate downwards around vertical axis forming the gravitomagnetic field which increases in horizontal size with increased rotation.
The exiting antigraviton creates the G-Force effect. It is repulsive to matter and high speed motion will hit this force field causing a buffeting effect and drag at high G motions. Rotating magnetic fields increase production of antigravitons creating lift and shielding against G-Forces. Let me know when you have your simulation up and working. John
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
this starts to get interesting seeing the thermodynamic effects of the vortex .. it looks like there is a spinning magnet experiment in order.. and then thinking how a current could be viewed as a spinning magnet.. how fast would it have to spin to get cold .. is there math for this or do we need the experiment to derive the math...
but if the idea is right then it would lead to some new torque electric motors,that would be geared to move the magnet as well as the electromagnet in the middle of the magnet! that could be resonant with a fuel cell...
if the feul cell is viewed as the capacitor and the motor a inductor,
im working on the circuit for the motor because it is a raising inductance so I need to make a reactive circuit, but the fuel cell will make hydrogen and oxygen that could be put back together to make more energy in resonance with the motor using the same water over and over agian, the motor would be very efficient, maybe over-unity efficient
MARX
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15 years 3 months ago #22989
by evolivid
To get a good view of what is really going on I will cycle through all the different equations
so in order to get this right then you can thank yourself later... thank you in advance for your constructive criticism, please feel free to correct when necessary.
with this equation cycle we can view everything that is going on between photon and energy transformations within any molecular system and how it effects other properties and matter
mc^2 = E = h/v = hf = h/WaveLength = UQ = UI(t)= P(t) = dW/(dt)Q = F(d)/(dt)e = (F/a)C^2 = (F/(v*t))c^2
please feel free to add any equation I might have missed, as I hope through this post this equation can get bigger, so that more properties can be evaluated.
MARX
Replied by evolivid on topic Reply from Mark Baker
To get a good view of what is really going on I will cycle through all the different equations
so in order to get this right then you can thank yourself later... thank you in advance for your constructive criticism, please feel free to correct when necessary.
with this equation cycle we can view everything that is going on between photon and energy transformations within any molecular system and how it effects other properties and matter
mc^2 = E = h/v = hf = h/WaveLength = UQ = UI(t)= P(t) = dW/(dt)Q = F(d)/(dt)e = (F/a)C^2 = (F/(v*t))c^2
please feel free to add any equation I might have missed, as I hope through this post this equation can get bigger, so that more properties can be evaluated.
MARX
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15 years 3 months ago #23530
by PhilJ
Replied by PhilJ on topic Reply from Philip Janes
evolivid: 01 Aug 2009 : 18:27:25<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">mc^2 = E = h/v = hf = h/WaveLength = UQ = UI(t)= P(t) = dW/(dt)Q = F(d)/(dt)e = (F/a)C^2 = (F/(v*t))c^2<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Why must I deduce that E is energy, h is Planck's constant, v (actually nu) is wavelength, f is frequency, U is electrical potential, I is current, t is time, P is power, F is force, d is distance (except where it means an increment of change in another variable), a is acceleration, c is speed of light, and v (English letter v) is velocity. It would be so much easier if you would tell us all that up front. If you change the meaning of a symbol, please don't make us guess that's what you did.
What is "W"? Is it work? What is "dW/(dt)Q"? Are these "d"s distance or an increment of change? Or is one distance and the other an increment of change?
If you mean, "Q times the time rate of changing W", then U is the time rate of changing W, so W is the time integral of U, whatever that means. Does W have dimensions of energy times time? Is it action or angular momentum?
Did you mean, "dW/(dt*Q)"? Please explain.
If "W" is work, are you saying "W = E"?
We're not all mind readers, here.
Fractal Foam Model of Universes: Creator
What is "W"? Is it work? What is "dW/(dt)Q"? Are these "d"s distance or an increment of change? Or is one distance and the other an increment of change?
If you mean, "Q times the time rate of changing W", then U is the time rate of changing W, so W is the time integral of U, whatever that means. Does W have dimensions of energy times time? Is it action or angular momentum?
Did you mean, "dW/(dt*Q)"? Please explain.
If "W" is work, are you saying "W = E"?
We're not all mind readers, here.
Fractal Foam Model of Universes: Creator
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15 years 3 months ago #22990
by evolivid
Replied by evolivid on topic Reply from Mark Baker
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by evolivid</i>
<br />
To get a good view of what is really going on I will cycle through all the different equations
so in order to get this right then you can thank yourself later... thank you in advance for your constructive criticism, please feel free to correct when necessary.
with this equation cycle we can view everything that is going on between photon and energy transformations within any molecular system and how it effects other properties and matter
mc^2 = E = hf = h/nu = UQ = UI(t)= P(t) = W/Q = F(d)/(dt)e = (F/a)c^2 = (F/(v*t))c^2.
I(t)/U = A*t/V = Farads.
U(t)/I = V*t/A = henrys.
e = electric charge.
m = rest mass.
c = speed of light.
h = Planck's constant.
v = velocity.
f = frequency.
nu = WaveLength.
U = electric potential.
Q = e = electric charge.
F = force.
P = power.
W = work.
a = acceleration.
I = current.
d = distance.
t = time.
V = volts.
A = amperes.
Farads = capacitance.
Henerys = inductance.
please feel free to add any equation I might have missed, as I hope through this post this equation can get bigger, so that more properties can be evaluated.
MARX
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
having this in a chain like this will help the final program
where a change in one equation effects the other.
MARX
<br />
To get a good view of what is really going on I will cycle through all the different equations
so in order to get this right then you can thank yourself later... thank you in advance for your constructive criticism, please feel free to correct when necessary.
with this equation cycle we can view everything that is going on between photon and energy transformations within any molecular system and how it effects other properties and matter
mc^2 = E = hf = h/nu = UQ = UI(t)= P(t) = W/Q = F(d)/(dt)e = (F/a)c^2 = (F/(v*t))c^2.
I(t)/U = A*t/V = Farads.
U(t)/I = V*t/A = henrys.
e = electric charge.
m = rest mass.
c = speed of light.
h = Planck's constant.
v = velocity.
f = frequency.
nu = WaveLength.
U = electric potential.
Q = e = electric charge.
F = force.
P = power.
W = work.
a = acceleration.
I = current.
d = distance.
t = time.
V = volts.
A = amperes.
Farads = capacitance.
Henerys = inductance.
please feel free to add any equation I might have missed, as I hope through this post this equation can get bigger, so that more properties can be evaluated.
MARX
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
having this in a chain like this will help the final program
where a change in one equation effects the other.
MARX
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15 years 3 months ago #22991
by PhilJ
Replied by PhilJ on topic Reply from Philip Janes
In the equation E = h/v, "v" is actually the Greek letter "nu". It is customary to substitute the letter "v" (which looks a lot like the letter "nu") when you are using a primative text editor which can't handle Greek letters. The energy of a photon is not equal to Planck's constant divided by velocity; it is equal to Planck's constant divided by wavelength.
You haven't answered my questions about "dW/(dt)Q". If both "d"s are distance, they you are saying that E = W/tQ, and it's not clear whether the Q belongs in the numerator or the devisor. If E = W, then you are saying that E = E/tQ. If Q is in the devisor, that means that tQ = 1; if Q is in the numerator, that means t = Q. If both "d"s are increments of change, then dW/dt is the rate of changing W, which is power; dW/dt = P.
Your next equation, "E = F(d)/(dt)e", is equally baffling. If "d" is distance, then F(d) = E, so (dt)e = 1. I think you are mixing formulas in which the same symbol has two very different meanings.
Where do you get, "(F/a)c^2 = (F/(v*t))c^2"? Velocity times time is distance, not acceleration.
What's the point of this string of supposed equalities, anyway? Why am I wasting my time pointing out how flawed they are?
Fractal Foam Model of Universes: Creator
You haven't answered my questions about "dW/(dt)Q". If both "d"s are distance, they you are saying that E = W/tQ, and it's not clear whether the Q belongs in the numerator or the devisor. If E = W, then you are saying that E = E/tQ. If Q is in the devisor, that means that tQ = 1; if Q is in the numerator, that means t = Q. If both "d"s are increments of change, then dW/dt is the rate of changing W, which is power; dW/dt = P.
Your next equation, "E = F(d)/(dt)e", is equally baffling. If "d" is distance, then F(d) = E, so (dt)e = 1. I think you are mixing formulas in which the same symbol has two very different meanings.
Where do you get, "(F/a)c^2 = (F/(v*t))c^2"? Velocity times time is distance, not acceleration.
What's the point of this string of supposed equalities, anyway? Why am I wasting my time pointing out how flawed they are?
Fractal Foam Model of Universes: Creator
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15 years 3 months ago #23808
by evolivid
Replied by evolivid on topic Reply from Mark Baker
The reason for the string is to look at what is going on with all the different
points of view of a electron at rest, and to find its capacitance and inductance.
In my electronics book W/Q = E but this is the EMF in volts
E = mc^2 is in Joules so im trying to figure out how many
volts are in a Joule since the charge of the electron is (e) and e is equal to Q
and Q is equal to I(t) so I know the amperage of the electron
in 1 joule there is 6241506408000000000 electron Volts
and 1 electron volt * 1 volt = 1.60*10^-19 Joules
and 1 joule = 0.00027777777778 watthour
1 joule = 1 wattsecond
so how many volts are in a Joule ???
if I know the rest Mass voltage and the rest Mass current then I will know
its inductance and its capacitance , which means I will know its resonant frequancy
which means I can determine the positrons inductance and capacitance
which means that I can find there resonant frequency which means I can
automatically plot the movments of quarks in a proton based on my model
which means I can plot any chemical reaction known to man with better accuracy then quantum mechanics
MARX
points of view of a electron at rest, and to find its capacitance and inductance.
In my electronics book W/Q = E but this is the EMF in volts
E = mc^2 is in Joules so im trying to figure out how many
volts are in a Joule since the charge of the electron is (e) and e is equal to Q
and Q is equal to I(t) so I know the amperage of the electron
in 1 joule there is 6241506408000000000 electron Volts
and 1 electron volt * 1 volt = 1.60*10^-19 Joules
and 1 joule = 0.00027777777778 watthour
1 joule = 1 wattsecond
so how many volts are in a Joule ???
if I know the rest Mass voltage and the rest Mass current then I will know
its inductance and its capacitance , which means I will know its resonant frequancy
which means I can determine the positrons inductance and capacitance
which means that I can find there resonant frequency which means I can
automatically plot the movments of quarks in a proton based on my model
which means I can plot any chemical reaction known to man with better accuracy then quantum mechanics
MARX
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