Gravitons and Push Gravity question.

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19 years 10 months ago #12135 by north
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or since the way i look at it the core of the earth is probably plasmic, no solid core,iron. since a plasmic condition of the earth would give the earth a magnetic field, which means i'm in line with what cosmicssurfer suggested before.

and for the life of me i can not picture some object bobbing around this hole in the earth, where one end of the hole meats the other, unless there was magnetics involved here. it just does not seem plausible to me.

is there a way to convince me otherwise?

since gravity is suppose to be 9m/sec^2 and then going through this hole the momentum would just keep increaseing, what at any point would have the potential to decrease this momentum, if there is no opposite mass to collide with it to slow it down? i mean looking at the other end, it is only 9m/sec^2 since from the opposite end nothing is being accelerated,so the mass entrance end has way more energy than the opposite end since gravity is mass dependant and of course much overwhelms the opposite direction. therefore the mass goes right out the other side and into space!!

to show this i would calculate the several hundred miles to the earths core by 9m/sec^2 and then find what is going to stop this accleration at the mid point. i'll tell you nothing!! out the shute it goes!!

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19 years 10 months ago #11020 by tvanflandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by rousejohnny</i>
<br />What is it that makes the gravitational potential greater at the poles?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">In conventional (math-only) terms, the poles are closer to Earth's mass than points on the equator, so gravitational potential (which is -GM/r) is stronger at the poles.

In current thinking about gravity (which explains all related phenomena in physical terms), the stronger gravitational potential at the poles means that the stronger gravitational force there compresses the elysium more and makes it denser. Electromagnetic phenomena such as atomic clocks propagate and function slower where elysium (the light-carrying medium) is denser.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Is it not the bulge of mass at the equator. Is this bulge not generated by the centrifugal force of a spinning sphere. Does the bulging not recend towards the poles using centrifugal considerations in determining the gravitational potential of a given latitude?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">I suppose you might look at it that way. But I see these as accompanying phenomena, not causal phenomena. Centrifugal force is not the cause of clock-slowing, as can be seen in direct experiments. For example, clocks at various altitudes over the poles change their rates in response to changing gravitational potential, yet there is no centrifugal force. And clocks on planes flying in a line (no centrifugal force) or flying in a tight circle (with centrifugal force) tick at the same rate. -|Tom|-

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19 years 10 months ago #12265 by tvanflandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by north</i>
<br />i can not picture some object bobbing around this hole in the earth, where one end of the hole meets the other, unless there was magnetics involved here. it just does not seem plausible to me. is there a way to convince me otherwise?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">That depends on what you know about gravity. Do you accept Newton's universal law, that the acceleration due to gravity anywhere outside a body is GM/r^2 directed toward the center of mass? And the acceleration inside any uniform spherical shell is everywhere zero?

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">since gravity is suppose to be 9m/sec^2 and then going through this hole the momentum would just keep increaseing<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">No, that is the acceleration at Earth's surface. The acceleration decreases smoothly to zero as a test body approaches Earth's center because that body is inside more and more spherical shells of Earth-mass. Then at the center, acceleration is zero, velocity is a maximum, and the test body shoots by and heads toward the surface on the opposite side. As it goes, acceleration builds up again, but this time directed back toward the center, which causes the test body to slow down. Because of symmetry in the acceleration values, the test mass velocity will reach zero at the Earth's surface on the far side of the hole. It will then start falling again and repeat the cycle. Total energy and momentum are always conserved.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">what at any point would have the potential to decrease this momentum, if there is no opposite mass to collide with it to slow it down?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">The direction of gravitational force is first one way, dropping to zero, then increasing the opposite way, always directed toward the center. -|Tom|-

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19 years 10 months ago #12266 by north
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<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by tvanflandern</i>
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by north</i>
<br />i can not picture some object bobbing around this hole in the earth, where one end of the hole meets the other, unless there was magnetics involved here. it just does not seem plausible to me. is there a way to convince me otherwise?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

That depends on what you know about gravity. Do you accept Newton's universal law, that the acceleration due to gravity anywhere outside a body is GM/r^2 directed toward the center of mass? And the acceleration inside any uniform spherical shell is everywhere zero?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

first,is Newtons universal law accepted as true?

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19 years 10 months ago #12136 by tvanflandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by north</i>
<br />first, is Newtons universal law accepted as true?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">It has never failed to make correct predictions in any situation where it is applicable, whether in the laboratory, for the solar system, or in double stars or star clusters. That includes both natural and made-made objects such as artificial satellites and spacecraft. There are issues for extreme cases, such as the "dark matter" controversy for galactic dynamics. But for all ordinary cases, Newton's universal law has always been good for 6-8 decimal places of precision. -|Tom|-

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19 years 10 months ago #12267 by north
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<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by tvanflandern</i>
<br /><blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by north</i>
<br />first, is Newtons universal law accepted as true?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">It has never failed to make correct predictions in any situation where it is applicable, whether in the laboratory, for the solar system, or in double stars or star clusters. That includes both natural and made-made objects such as artificial satellites and spacecraft. There are issues for extreme cases, such as the "dark matter" controversy for galactic dynamics. But for all ordinary cases, Newton's universal law has always been good for 6-8 decimal places of precision. -|Tom|-
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

what is ordinary cases? for the solar system and satellites i know that Newtonian physics is applicable.

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