Requiem for Relativity

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13 years 10 months ago #21073 by shando
Replied by shando on topic Reply from Jim Shand
There is supposed to be a post by Joe Keller stamped: 28 Dec 2010 12:21:43. Why can't I view it?

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13 years 10 months ago #21074 by Stoat
Replied by Stoat on topic Reply from Robert Turner
Hi Shando, it's probably that Joe has edited one of his posts, that shows as a last posting.

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13 years 10 months ago #21072 by Joe Keller
Replied by Joe Keller on topic Reply from
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />...Joe, how do you think it relates to the fission v collision models of planetary formation?
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

I agree, that this fact, that usually a body in our solar system conforms to the formula in my first Dec. 7, 2010, post here, must result from the mechanism of formation. The golden ratio, 1.618... , satisfies the quadratic equation

x^2-x-1=0

and the equations satisfied by powers of a root, are related to the original equation (see Fritz John, "Lectures on Advanced Numerical Analysis", sec. 2.9, "Graeffe Root-Squaring Process", pp. 53-56). Somehow, one of this special family of equations must be satisfied.

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13 years 10 months ago #21075 by Joe Keller
Replied by Joe Keller on topic Reply from
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Jim</i>
<br />..."n"...what it is and what units it has?
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

"n" is the exponent of 1.618... . It's dimensionless (it has no units, that is, its value is the same no matter what the units of measurement are).

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13 years 10 months ago #24111 by Joe Keller
Replied by Joe Keller on topic Reply from
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by shando</i>
<br />...a post by Joe Keller stamped: 28 Dec 2010 12:21:43. Why can't I view it?
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">

Stoat's explanation is right: I submitted my long article on Mars' orbital period, to a journal early this month, then on Dec. 28 improved it.

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13 years 10 months ago #21076 by Joe Keller
Replied by Joe Keller on topic Reply from
The July 15 & 22, 2008, Avebury Crop Circles: 2012 & Barbarossa

For pictures of the crop formations, see www.realufos.net , blog article dated Aug. 1, 2008 (find by typing "Avebury 2008 2012 July" in that site's search window).

The July 15 crop formation, I've discussed in earlier posts to this thread. The consensus of crop circle expert opinion is that this formation shows the positions of the planets (except that Pluto is perturbed) for Dec. 23, 2012. I myself confirmed that this is true to within a few days.

The less well known nearby second formation, of July 22, was, according to commentary on www.realufos.net , unexplainedly censored by usually reliable sources. It shows, among other things, a small ellipse.

If I measure from the centers of the small circles along that small ellipse, I find that its eccentricity is about the same as the eccentricity of Barbarossa's orbit. Using the apparent (perspective) axis ratio of Neptune's orbit on the same photo (in the July 15 circle), to correct for perspective by multiplying the minor axis of the small ellipse by that factor, I get eccentricity 0.68 based on the small ellipse's axis ratio. Based on the position of the presumed "Sun" mark, i.e. focus, on the long axis of the small ellipse, I get eccentricity 0.53. Thus the best estimate is e=0.605+/-0.053 (SEM). Barbarossa's eccentricity calculated from the sky survey positions, is e=0.6106.

The large circle (of the second formation, July 22) has a small circle attached to it, on the side near the original July 15 formation; the small circle might signify Neptune's orbit and the large circle Barbarossa's. The ratio of the circles' radii (measuring all the way to the edge of the thick white line demarcating the small circle) is about 11.8::1. The ratio of Barbarossa's to Neptune's major axes, is 343.84/30.07 = 11.4::1.

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