Nuclear fusion in the Meta Model

The way thermodynamic properties are used in nuclear processes makes no sense because what is generated in fusion isn't thermal. The particles are high energy and high frequency for sure-not thermal. This detail is smoothed over by doing the math wrong. A more real model can be developed by doing away with temperature and using the frequency instead. It seems like a minor detail but if you get down and dirty about it the minor details like this are most important.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Astrodelugeologist</i>
<br />As far as I know, the Meta Model does not rely on quantum mechanics. That leaves us with classical mechanics.

In order to achieve nuclear fusion, the Coulomb barrier (electromagnetic repulsion between protons) must be overcome so that the particles can move close enough together for the strong nuclear force to be effective.

According to classical mechanics, the temperature required for this to occur is 10,000,000,000 K. The central temperature of the Sun is only about 16,000,000 K. By classical mechanics alone, this means that the Sun is too cool by three orders of magnitude to sustain nuclear fusion.

According to quantum mechanics, the temperature required for nuclear fusion is about 10,000,000 K. This would allow for nuclear fusion in the Sun.

Since the Meta Model rejects quantum mechanics, don't we need another model for stellar nuclear fusion? And does such an alternative model exist?

I have one idea, but I haven't done the math, so I'll refrain from stating it at this time.

--Astro
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Temperature alone is not the sole criteria for fusion. It is called "Lawsons Criteria" and involves temperature, time and density.

"Imagination is more important than Knowledge" -- Albert Einstien

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Astrodelugeologist</i>
<br />As far as I know, the Meta Model does not rely on quantum mechanics. That leaves us with classical mechanics.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">QM and MM have the same math, but different physical interpretations. With that qualification, what you say about MM drawing from classical mechanics is true.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">In order to achieve nuclear fusion, the Coulomb barrier (electromagnetic repulsion between protons) must be overcome so that the particles can move close enough together for the strong nuclear force to be effective.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">That's QM-based reasoning, not MM. We must first have a physical model for electromagnetic repulsion, which MM has and QM doesn't have. For MM, that was presented in "The Structure of Matter in the Meta Model", MRB 12:58-63 (2003). The repulsion is produced by entrained elysium atmospheres around charges -- atmospheres that have a sponge-like character. Once the elysium envelopes around charges start to be breached, the process of penetration gets easier and easier until the merged elysium envelopes operate to hold both charges together. I.e., repulsion smoothly transitions into the strong nuclear force. In QM, which lacks a physical model, these must be two separate forces.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">According to classical mechanics, the temperature required for this to occur is 10,000,000,000 K. The central temperature of the Sun is only about 16,000,000 K. By classical mechanics alone, this means that the Sun is too cool by three orders of magnitude to sustain nuclear fusion. According to quantum mechanics, the temperature required for nuclear fusion is about 10,000,000 K. This would allow for nuclear fusion in the Sun.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">This very different MM physical model of what is happening can probably use similar math as in QM, so it would have a similar temperature requirement.

<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote">Since the Meta Model rejects quantum mechanics, don't we need another model for stellar nuclear fusion?<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">No, MM is the most complete physical model that exists today.

It should also be noted that nuclear fusion itself is a classical process in MM, with the heat source being graviton absorption. This is explained in my chapter in <i>Pushing Gravity</i>. -|Tom|-

Wow. This is a lot simpler than the Standard Model. You've explained two forces with a single mechanism. I'm impressed.

I don't know what you mean by "similar math", but the QM model for stellar fusion relies on quantum tunneling and the Heisenberg Uncertainty Principle. I don't see how any classical model could emulate these.

If your model is correct, I would expect that the "height" of the nuclear potential would be less than QM suggests. This would lower the required temperature for fusion accordingly.

--Astro