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Are Electrostatic forces Asymmetric?
- AgoraBasta
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22 years 3 months ago #2861
by AgoraBasta
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Nice idea, btw. And repulsion of alike charges really is slightly smaller, that's due to the fact that charges never come massless. The problem here is that mass/charge ratio is hopelessly different for various elementary particles, which in turn must be a result of nature having also weak and strong interactions for those elementary particles. So it's easier to consider Coulomb field as a kind of highly asymmetric gravity, than the other way around.
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- KoenigMKII
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22 years 3 months ago #2972
by KoenigMKII
Replied by KoenigMKII on topic Reply from Neil Laverty
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
Nice idea, btw. And repulsion of alike charges really is slightly smaller, that's due to the fact that charges never come massless. The problem here is that mass/charge ratio is hopelessly different for various elementary particles, which in turn must be a result of nature having also weak and strong interactions for those elementary particles. So it's easier to consider Coulomb field as a kind of highly asymmetric gravity, than the other way around.
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
The mass/charge ratio is a “show-stopper” if I accept that the final sub-division of nucleons in matter is the quark with its fractional charge. But what if the quark is itself sub-divided into smaller particles, which when you sum their charge give the charge value of the quark.
Now taking the modulus of all the “sub-quark” charges in a Proton and summing them together, it is perhaps possible to satisfy the known Net charge/mass ratio of that particle.
At this point I have to duck under Occam’s razor, for my sin of adding extra complexity, with the defense that if T.V.F is correct about G.R.'s equations being internally consistant, but not describing how nature is observed to behave, we actually need to answer the question:- “What IS Gravity?”
If “Gravity” is the local vector sum of all the electstatic forces acting on a particle, the observed effect of a clock increasing in rate as its altitude above the earth increases is explainable with the idea of all charges being wave like according to quantum theory.
If a clock is a macro collection of all these waves, the clock speeds up in rate if the “medium” of the electrostatic field decreases in “density.” (lines of equal potential become more widely spaced)
This idea is at least testable in a lab, if an asymmetric electrostatic field is traversed by a light ray that is itself being reflected between two mirrors, then even a minute deflection of the light ray should eventually be measured.
I am terrible at devising experiments, but if we have a stable cascade of light rays in a modified (both mirrors are 100% relecting) laser tube, shouldn’t a massive electrostatic gradient caused by switching on a megavolt Van de Graaf generator adjacent to the tube cause the L.A.S.E.R effect to leak energy out of the side of the laser?
I had better stop now, in case I hurt myself
Nice idea, btw. And repulsion of alike charges really is slightly smaller, that's due to the fact that charges never come massless. The problem here is that mass/charge ratio is hopelessly different for various elementary particles, which in turn must be a result of nature having also weak and strong interactions for those elementary particles. So it's easier to consider Coulomb field as a kind of highly asymmetric gravity, than the other way around.
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
The mass/charge ratio is a “show-stopper” if I accept that the final sub-division of nucleons in matter is the quark with its fractional charge. But what if the quark is itself sub-divided into smaller particles, which when you sum their charge give the charge value of the quark.
Now taking the modulus of all the “sub-quark” charges in a Proton and summing them together, it is perhaps possible to satisfy the known Net charge/mass ratio of that particle.
At this point I have to duck under Occam’s razor, for my sin of adding extra complexity, with the defense that if T.V.F is correct about G.R.'s equations being internally consistant, but not describing how nature is observed to behave, we actually need to answer the question:- “What IS Gravity?”
If “Gravity” is the local vector sum of all the electstatic forces acting on a particle, the observed effect of a clock increasing in rate as its altitude above the earth increases is explainable with the idea of all charges being wave like according to quantum theory.
If a clock is a macro collection of all these waves, the clock speeds up in rate if the “medium” of the electrostatic field decreases in “density.” (lines of equal potential become more widely spaced)
This idea is at least testable in a lab, if an asymmetric electrostatic field is traversed by a light ray that is itself being reflected between two mirrors, then even a minute deflection of the light ray should eventually be measured.
I am terrible at devising experiments, but if we have a stable cascade of light rays in a modified (both mirrors are 100% relecting) laser tube, shouldn’t a massive electrostatic gradient caused by switching on a megavolt Van de Graaf generator adjacent to the tube cause the L.A.S.E.R effect to leak energy out of the side of the laser?
I had better stop now, in case I hurt myself
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22 years 3 months ago #3283
by dholeman
Replied by dholeman on topic Reply from Don Holeman
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>
If “Gravity” is the local vector sum of all the electstatic forces acting on a particle,
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
According to the meta model gravity is the result of extrordinarily tiny particles called gravitons which impinge on a body at ultra-high velocity (>>> c) from all directions and which are partially absorbed or deflected by the bodies which they pass through. Gravity has nothing to do whatever with electrostatic charges in the sense that you present here, although thinking in terms of mechanisms to explain gravity is the first step in the right direction.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote> the observed effect of a clock increasing in rate as its altitude above the earth increases is explainable with the idea of all charges being wave like according to quantum theory.<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
I don't know where you've been making your observations but the closest such observation that I know of is a <i>"decrease"</i> in "clock speed" as the velocity of a test clock increases relative to a stationary observer (such as occurs in earth orbit). This is the well know relativistic time dilation effect of Einstein's Theory of Relativity. No explaination for this effect that I know of, Einsteinian or otherwise, is based on electrostatics.
I recommend two books which might satisfy your curiosity. Tom's book Dark Matter, Missing Planets and New Comets (2nd edition) is a good start, as it describes the Meta Model of gravitation. The other is Pushing Gravity, which contains a couple of discussions of gravitational models which incorporate electromagnetic fields in thier conceptions.
Best,
Don Holeman
If “Gravity” is the local vector sum of all the electstatic forces acting on a particle,
<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
According to the meta model gravity is the result of extrordinarily tiny particles called gravitons which impinge on a body at ultra-high velocity (>>> c) from all directions and which are partially absorbed or deflected by the bodies which they pass through. Gravity has nothing to do whatever with electrostatic charges in the sense that you present here, although thinking in terms of mechanisms to explain gravity is the first step in the right direction.
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote> the observed effect of a clock increasing in rate as its altitude above the earth increases is explainable with the idea of all charges being wave like according to quantum theory.<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
I don't know where you've been making your observations but the closest such observation that I know of is a <i>"decrease"</i> in "clock speed" as the velocity of a test clock increases relative to a stationary observer (such as occurs in earth orbit). This is the well know relativistic time dilation effect of Einstein's Theory of Relativity. No explaination for this effect that I know of, Einsteinian or otherwise, is based on electrostatics.
I recommend two books which might satisfy your curiosity. Tom's book Dark Matter, Missing Planets and New Comets (2nd edition) is a good start, as it describes the Meta Model of gravitation. The other is Pushing Gravity, which contains a couple of discussions of gravitational models which incorporate electromagnetic fields in thier conceptions.
Best,
Don Holeman
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22 years 3 months ago #2866
by Atko
Replied by Atko on topic Reply from Paul Atkinson
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote>I don't know where you've been making your observations but the closest such observation that I know of is a "decrease" in "clock speed" as the velocity of a test clock increases relative to a stationary observer (such as occurs in earth orbit). This is the well know relativistic time dilation effect of Einstein's Theory of Relativity <hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
This is true of clocks under the effects of acceleration, but clocks which are relatively stationary at high altitudes do run faster. This is due to the decreased influence of gravity, and was tested with some precision by Vessot et al in 1980. They launched a hydrogen maser straight up at 8.5 km/sec, and monitored its frequency change as it coasted up to about 10,000 km altitude and then fell back to Earth. The frequency shift due to gravity was (f'/f -1) = 4*10-10 at 10,000km.
This is true of clocks under the effects of acceleration, but clocks which are relatively stationary at high altitudes do run faster. This is due to the decreased influence of gravity, and was tested with some precision by Vessot et al in 1980. They launched a hydrogen maser straight up at 8.5 km/sec, and monitored its frequency change as it coasted up to about 10,000 km altitude and then fell back to Earth. The frequency shift due to gravity was (f'/f -1) = 4*10-10 at 10,000km.
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22 years 3 months ago #2873
by dholeman
Replied by dholeman on topic Reply from Don Holeman
<BLOCKQUOTE id=quote><font size=2 face="Verdana, Arial, Helvetica" id=quote>quote:<hr height=1 noshade id=quote> clocks which are relatively stationary at high altitudes do run faster. This is due to the decreased influence of gravity, and was tested with some precision by Vessot et al in 1980. They launched a hydrogen maser straight up at 8.5 km/sec, and monitored its frequency change as it coasted up to about 10,000 km altitude and then fell back to Earth. The frequency shift due to gravity was (f'/f -1) = 4*10-10 at 10,000km.<hr height=1 noshade id=quote></BLOCKQUOTE id=quote></font id=quote><font face="Verdana, Arial, Helvetica" size=2 id=quote>
I found this Harvard website describing the use of a maser clock in the fashion that you describe. [url] cfa-www.harvard.edu/hmc/ I'm about to start reading Halton Arp's book and probably should wait before commenting further on but at this point I'm thinking something like redshift of maser frequencies as a result of decreased gravity seems to fit right into the Meta Model and I'm not at all sure that relativistic time frame shifting is the explaination for it. Is it possible that time was not affected but instead the particular mechanism used to measure time was affected? They don't mention sending up a timex watch as an experimantal control but I wonder if similar experiments using other clocking mechanisms than those dependent on EMF have been conducted.
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I found this Harvard website describing the use of a maser clock in the fashion that you describe. [url] cfa-www.harvard.edu/hmc/ I'm about to start reading Halton Arp's book and probably should wait before commenting further on but at this point I'm thinking something like redshift of maser frequencies as a result of decreased gravity seems to fit right into the Meta Model and I'm not at all sure that relativistic time frame shifting is the explaination for it. Is it possible that time was not affected but instead the particular mechanism used to measure time was affected? They don't mention sending up a timex watch as an experimantal control but I wonder if similar experiments using other clocking mechanisms than those dependent on EMF have been conducted.
[/url]
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- KoenigMKII
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22 years 3 months ago #2874
by KoenigMKII
Replied by KoenigMKII on topic Reply from Neil Laverty
Just in case I have not made a big enough fool of myself here is a conjecture that follows on from my first post.
IF gravity is a local vector sum of all electrostatic forces acting at a particular test mass's coordinates AND IF light (photons) can be deflected by a massive gradient in that electrostatic field, does this meen Zero Point Energy (the short lived photons making up Quantum theory's "Dirac sea") can be partially deflected by a
massive electrostatic gradient??
In particular I am thinking of the following (IMHO)poorly explained effects in Physics:-
1/ the Biefeld-Brown effect (relativists start having major fits if you say this effect works in a Vaccuum)
[url][/url]jnaudin.free.fr/html/ehdev1.htm
2/ the Casimir effect between two oppositely charged metal plates as they are brought into very close proximity (there is a slight repulsive force detected.)
Any opinions or feedback appreciated, be as harsh as you like.
IF gravity is a local vector sum of all electrostatic forces acting at a particular test mass's coordinates AND IF light (photons) can be deflected by a massive gradient in that electrostatic field, does this meen Zero Point Energy (the short lived photons making up Quantum theory's "Dirac sea") can be partially deflected by a
massive electrostatic gradient??
In particular I am thinking of the following (IMHO)poorly explained effects in Physics:-
1/ the Biefeld-Brown effect (relativists start having major fits if you say this effect works in a Vaccuum)
[url][/url]jnaudin.free.fr/html/ehdev1.htm
2/ the Casimir effect between two oppositely charged metal plates as they are brought into very close proximity (there is a slight repulsive force detected.)
Any opinions or feedback appreciated, be as harsh as you like.
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