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Theory of Replication
15 years 11 months ago #15215
by Stoat
Replied by Stoat on topic Reply from Robert Turner
Heres' an interesting little oddity that I think we should kick about a bit. Let's suppose we have a vacuum particle which has a wavelength of h. Then from Lambda = h / mc we must have a mass of, the reciprocal of the speed of light.
So lets put that into the equation for the Shwartzchild radius
r = 2Gm / c^2
That gives us a radius of 4.95293156276E-36 metres. So how much smaller than h is that? 7.47490963958E-03 Thats' reciprocal is 1.33780881404E 02 Which isn't that far off the fine structure constant.
So lets put that into the equation for the Shwartzchild radius
r = 2Gm / c^2
That gives us a radius of 4.95293156276E-36 metres. So how much smaller than h is that? 7.47490963958E-03 Thats' reciprocal is 1.33780881404E 02 Which isn't that far off the fine structure constant.
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15 years 10 months ago #23575
by evolivid
Replied by evolivid on topic Reply from Mark Baker
Hey Stoat
Take a look www.Wolfram.com
many advances in the scientific realm have been made with help from mathematica
I find it to be a very usefull tool
MARX
Take a look www.Wolfram.com
many advances in the scientific realm have been made with help from mathematica
I find it to be a very usefull tool
MARX
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15 years 10 months ago #23663
by Stoat
Replied by Stoat on topic Reply from Robert Turner
Hi Mark, got that program, and something called maple. Take a million years for me to learn it, as I'm thick as two short planks[]
I've been thinking about the lorentzian as simply the equation of an ellipse. I think we have to throw in a z axis as well. So, we've got x^2 / a^2 + y^2 / b^2 + z^2 / c^2 = 1
(that c is not the speed of light)
y^2 / b^2 = 1 - 2 (x^2 /a^2)
I've assumed that x^2 / a^2 = z^2 / c^2 here. now that will double the energy of any particle but we can lose it by having a negative refractive index for a particle's Schwartchild core.
The ellipse again, take the root, y = b sqrt (1 - x^2 / a^2)
(that's the fitzgerald length contraction)
What about the mass contraction? It's the reciprocal. b = y / sqrt (1 - x^2 / a^2)
That's not an ellipse but a hyperbola.
Let's have a phase transition at the speed of light. We write x^2 / a^2 = 1 / eta^2 and give it a negative refractive index, so that the minus sign becomes a plus sign. It's back to being the equation of an ellipse.
But the value a, the major axis, is much much larger than the value b, the semi-major axis, b is the speed of light and "a" the speed of gravity. What we would end up with is a very flat ellipse. Pop the z axis back in and we have a disk with about the square root of h thickness at its centre.
But because we are allowing ourselves negative refractive index, that disk is the argand plane but a two sided curved argand plane.
It might be fun to play a kepler game with it, the negative x axis value focal point, is where something on an elliptical orbit is traveling at the speed of gravity but when it's near the other positive focal point it's slowed right down to c.
I've been thinking about the lorentzian as simply the equation of an ellipse. I think we have to throw in a z axis as well. So, we've got x^2 / a^2 + y^2 / b^2 + z^2 / c^2 = 1
(that c is not the speed of light)
y^2 / b^2 = 1 - 2 (x^2 /a^2)
I've assumed that x^2 / a^2 = z^2 / c^2 here. now that will double the energy of any particle but we can lose it by having a negative refractive index for a particle's Schwartchild core.
The ellipse again, take the root, y = b sqrt (1 - x^2 / a^2)
(that's the fitzgerald length contraction)
What about the mass contraction? It's the reciprocal. b = y / sqrt (1 - x^2 / a^2)
That's not an ellipse but a hyperbola.
Let's have a phase transition at the speed of light. We write x^2 / a^2 = 1 / eta^2 and give it a negative refractive index, so that the minus sign becomes a plus sign. It's back to being the equation of an ellipse.
But the value a, the major axis, is much much larger than the value b, the semi-major axis, b is the speed of light and "a" the speed of gravity. What we would end up with is a very flat ellipse. Pop the z axis back in and we have a disk with about the square root of h thickness at its centre.
But because we are allowing ourselves negative refractive index, that disk is the argand plane but a two sided curved argand plane.
It might be fun to play a kepler game with it, the negative x axis value focal point, is where something on an elliptical orbit is traveling at the speed of gravity but when it's near the other positive focal point it's slowed right down to c.
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