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The entropy of systems
17 years 11 months ago #15075
by GD
Replied by GD on topic Reply from
I'll get back to you on this.
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- Larry Burford
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17 years 11 months ago #17863
by Larry Burford
Replied by Larry Burford on topic Reply from Larry Burford
[GD] "These three equations lack one key variable to show varying energy with time: acceleration.
E = (1/2)*m*v^2
E = m*g*h
E = m*c^2
"
Wrong.
This is great example of what I'm talking about. If you understood units you would would realize that each of your example equations does in fact contain acceleration.
One of them contains it explicitly, the other two contain it in a slightly disguised manner.
LB
E = (1/2)*m*v^2
E = m*g*h
E = m*c^2
"
Wrong.
This is great example of what I'm talking about. If you understood units you would would realize that each of your example equations does in fact contain acceleration.
One of them contains it explicitly, the other two contain it in a slightly disguised manner.
LB
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- Larry Burford
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17 years 11 months ago #18960
by Larry Burford
Replied by Larry Burford on topic Reply from Larry Burford
OK, I see you retracted your post. Perhaps you are beginning to see the light?
LB
LB
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17 years 11 months ago #18947
by GD
Replied by GD on topic Reply from
This is somewhat what I had posted earlier:
E=1/2mv^2 means energy related to velocity (change in velocity missing)
E=mgh means energy related to position (change in position missing)
E=mc^2 means a mass converting into energy (change in entropy missing)
The theory of a non-equilibrium state of the universe would imply a varying level of energy of the atom with time.
In the equations above, if we vary energy and mass, then velocity has to vary also. Therefore the missing variable is acceleration.
Acceleration would signify: change in position, velocity & entropy.
If the entropy of a system varies then, pressure, temperature, velocity, and inertia also varies.
You will notice that the links that I have been posting could agree with the non-equilibrium state of the atom. This is practically proven already, all I am missing is the equation.
First, I will search the web for a formula which resembles this. This will take some time.
E=1/2mv^2 means energy related to velocity (change in velocity missing)
E=mgh means energy related to position (change in position missing)
E=mc^2 means a mass converting into energy (change in entropy missing)
The theory of a non-equilibrium state of the universe would imply a varying level of energy of the atom with time.
In the equations above, if we vary energy and mass, then velocity has to vary also. Therefore the missing variable is acceleration.
Acceleration would signify: change in position, velocity & entropy.
If the entropy of a system varies then, pressure, temperature, velocity, and inertia also varies.
You will notice that the links that I have been posting could agree with the non-equilibrium state of the atom. This is practically proven already, all I am missing is the equation.
First, I will search the web for a formula which resembles this. This will take some time.
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17 years 11 months ago #18961
by GD
Replied by GD on topic Reply from
Larry,
You will have to explain to me how energy of a system varies in those three equations...
Then I'll see the light.
You will have to explain to me how energy of a system varies in those three equations...
Then I'll see the light.
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- tvanflandern
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17 years 11 months ago #18962
by tvanflandern
Replied by tvanflandern on topic Reply from Tom Van Flandern
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by GD</i>
<br />In the equations above, if we vary energy and mass, then velocity has to vary also. Therefore the missing variable is acceleration. Acceleration would signify: change in position, velocity & entropy.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Focussing on just the main problem with this ...
Changes in velocities are still velocities. But they are <i>not</i> accelerations. Acceleration is the <i>time rate of change</i> of velocity. Acceleration is <i>not</i> a change in velocity.
Suppose you have $100, and lose $10, Then you have $90 left. All of these have the same units, dollars, and all represent amounts of money.
Now suppose you lose money at the rate of $10 per hour. If you do nothing to change this, all your money will be gone in 10 hours. The $10/hr rate has different units ($/hr) from those of amounts ($). So a rate by itself does not represent any particular amount of money, and a change in the amount of money does not represent a rate.
If you compared someone's rate of gain or loss of money to the size of someone else's fortune, it would make no sense. The same is true of comparing an acceleration to a velocity.
You need to learn these basics before talking to others because you can't help betraying that you don't know the basics if you have not, in fact, learned them. -|Tom|-
<br />In the equations above, if we vary energy and mass, then velocity has to vary also. Therefore the missing variable is acceleration. Acceleration would signify: change in position, velocity & entropy.<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">Focussing on just the main problem with this ...
Changes in velocities are still velocities. But they are <i>not</i> accelerations. Acceleration is the <i>time rate of change</i> of velocity. Acceleration is <i>not</i> a change in velocity.
Suppose you have $100, and lose $10, Then you have $90 left. All of these have the same units, dollars, and all represent amounts of money.
Now suppose you lose money at the rate of $10 per hour. If you do nothing to change this, all your money will be gone in 10 hours. The $10/hr rate has different units ($/hr) from those of amounts ($). So a rate by itself does not represent any particular amount of money, and a change in the amount of money does not represent a rate.
If you compared someone's rate of gain or loss of money to the size of someone else's fortune, it would make no sense. The same is true of comparing an acceleration to a velocity.
You need to learn these basics before talking to others because you can't help betraying that you don't know the basics if you have not, in fact, learned them. -|Tom|-
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