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Requiem for Relativity
- Joe Keller
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14 years 1 month ago #23999
by Joe Keller
Replied by Joe Keller on topic Reply from
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />Hi Joe, you wouldn't happen to know of an "idiots guide to Lie algebra" would you? ...<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Hi Bob,
My best recommendation is van der Waerden, "Group Theory and Quantum Mechanics". I've only read a little of it, but I think it's the best book for your needs (or mine) on this subject. Lie (pronounced "Lee") groups cover a lot of ground which includes commonplace things like rotations and Lorentz transformations. There's no royal road to geometry, but I think van der Waerden is the best at laying out what one needs to know to do original research. Good luck!
- Joe Keller
<br />Hi Joe, you wouldn't happen to know of an "idiots guide to Lie algebra" would you? ...<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
Hi Bob,
My best recommendation is van der Waerden, "Group Theory and Quantum Mechanics". I've only read a little of it, but I think it's the best book for your needs (or mine) on this subject. Lie (pronounced "Lee") groups cover a lot of ground which includes commonplace things like rotations and Lorentz transformations. There's no royal road to geometry, but I think van der Waerden is the best at laying out what one needs to know to do original research. Good luck!
- Joe Keller
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14 years 1 month ago #24000
by Joe Keller
Replied by Joe Keller on topic Reply from
Digression on Knots
I tested some knots by tying them in braided cotton/polyester sewing thread (Coats & Clark "All Purpose Dual Duty Plus"). Using three lengths of thread tied together, with two knots, to make a triple length string, I tested the knots in pairs, one against the other. I used slowly increasing pulls, two trials for each knot pair. The results of the trials always agreed. The break was always at one knot or the other, never both, and never in the untied part. Strongest to weakest:
1. Flemish bend a.k.a. Figure Eight Bend
2. Reever bend
3. Rosendahl bend aka Zeppelin Bend
4. Carrick bend
5. Square knot aka Reef knot
I tested some knots by tying them in braided cotton/polyester sewing thread (Coats & Clark "All Purpose Dual Duty Plus"). Using three lengths of thread tied together, with two knots, to make a triple length string, I tested the knots in pairs, one against the other. I used slowly increasing pulls, two trials for each knot pair. The results of the trials always agreed. The break was always at one knot or the other, never both, and never in the untied part. Strongest to weakest:
1. Flemish bend a.k.a. Figure Eight Bend
2. Reever bend
3. Rosendahl bend aka Zeppelin Bend
4. Carrick bend
5. Square knot aka Reef knot
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14 years 1 month ago #24001
by Stoat
Replied by Stoat on topic Reply from Robert Turner
Hi Joe, thanks for the info. I've been thinking about knots just lately as well. It seems that the human Y chromosome has large blocks of palindromic code. This is thought to aid its stability, as it doesn't have a duplicate of itself like the X chromosome. So I thought, we can take any "word" and duplicate the letters and reverse them. I thought, mississippi; as it has four characters. That would give us a palindrome of "mississippiip****issim"
Where the knot comes in. Mitochondrial dna forms itself into a loop. Lets make a loop of three of those mississippi palindromes, which will form a helix that joins up. It has to join up in such a way that the verticals of the dna ladder have a sugar that joins to a phosphate on each leg.
Well this is a mobius and we're going to get six crossing points, three of which are going to be a trefoil knot. The crossing points can slide over each other, so the dna in reproducing itself has to have cuts but there's no way of saying where they'll be in terms of our "words". In fact our "words" might not be meaningful code at all, all they have in terms of order might be the fact that they are palindromic. Note also that in that double mississippi word, we could drop one of the centre letter "i's" and still have a palindrome but that would mean having to put in an extra half twist, to get the legs of the ladder to meet up as sugar/phosphates.
That's about as far as I've got with it. What I've been thinking about, is the famous story of when Gauss, and his class, were told to add all of the numbers from one to a hundred. Gauss simply reversed the sequence, added the numbers, multiplied and then divided by two. A sort of palindrome.
Where the knot comes in. Mitochondrial dna forms itself into a loop. Lets make a loop of three of those mississippi palindromes, which will form a helix that joins up. It has to join up in such a way that the verticals of the dna ladder have a sugar that joins to a phosphate on each leg.
Well this is a mobius and we're going to get six crossing points, three of which are going to be a trefoil knot. The crossing points can slide over each other, so the dna in reproducing itself has to have cuts but there's no way of saying where they'll be in terms of our "words". In fact our "words" might not be meaningful code at all, all they have in terms of order might be the fact that they are palindromic. Note also that in that double mississippi word, we could drop one of the centre letter "i's" and still have a palindrome but that would mean having to put in an extra half twist, to get the legs of the ladder to meet up as sugar/phosphates.
That's about as far as I've got with it. What I've been thinking about, is the famous story of when Gauss, and his class, were told to add all of the numbers from one to a hundred. Gauss simply reversed the sequence, added the numbers, multiplied and then divided by two. A sort of palindrome.
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14 years 1 month ago #24002
by Joe Keller
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This letter emailed ten minutes ago, I'll post here because it's my current best "sales pitch". If anyone else wants to "sell" any proprietors of large telescopes, to search for Barbarossa, I'd suggest these arguments.
Dear Prof. *****,
I am a graduate of Harvard College, B. A. cumlaude in Mathematics, 1977. I am not a professional astronomer but nonetheless, what I tell you is "Veritas".
In Feb. 2007 I discovered (eventually, on all of the four existing relevant online Red and Optical Infrared sky surveys) a body near the longitude predicted by David Todd, Percival Lowell, and Robert Harrington. It is near the positive CMB dipole, suggesting an alternative explanation for the correlation of the CMB multipoles with the ecliptic. Even without correction for Earth parallax, the coplanarity and constancy of angular speed are statistically significant. Its Red and Optical Infrared magnitudes are ~ +18.5. The images show the "Eberhard effect" characteristic of real stellar images on photographic emulsions.
This is really Lowell's "Planet X". Not receiving any reply from the International Astronomical Union, I named the planet myself: Barbarossa, after the legendary sleeping crusader.
My orbit fitting gives a=384 AU, e=0.61, and P=6340 +/- 7 yr. For a mass ~0.01 solar, there is a "precession resonance" with Neptune, Pluto, and the classical Kuiper Belt: the precession period of these orbits due to the average torque exerted by Barbarossa, is 3x, 2x, or 1x the precession period of these orbits due to the torque exerted by the known planets. Goldreich's nonexistence proof is faulty.
For many pulsars, Pdot/P clusters near small multiples of H0. This shows that there is something we do not understand about distant radio signals, from pulsars in particular. The alleged lack of acceleration toward pulsars, also is a faulty nonexistence proof.
Two stars with exceptionally strong "interstellar absorption", 61 Leonis and Theta Crateris, lie behind Barbarossa. My tabulation showed that there is a statistically significant excess of discordant Red and Blue USNO-B catalog magnitudes in this region. Barbarossa has a nebula that moves with it.
The correct interpretation of the "Sothic" date of Amenhotep I, is that it really refers to a heliacal rising of Arcturus, and occurs in an Egyptian calendar beginning at the summer solstice, 4328 BC. This gives 6339.5 tropical yr between the beginning of the lost Egyptian calendar, and the end of the Mayan Long Count. With only ~5% error, sqrt(kT/m) = H0*c*P, where P is the period of Barbarossa, H0 the Hubble parameter as now measured, T the CMB temperature, and m the mass of the proton (or hydrogen atom). My literature search found that according to the present state of the art, almost no dogmatic statements can be made about the diameter, albedo, or surface temperature of Barbarossa, a partially gravitationally collapsed body of unknown composition and origin.
I would be happy to meet with any or all faculty members of the University of ***** Astronomy Dept. in October for discussion. It is convenient for me to visit ***** then, because *********.
Sincerely,
Joseph C. Keller, M. D.
... POB 9122, Ames, Iowa 50014
Dear Prof. *****,
I am a graduate of Harvard College, B. A. cumlaude in Mathematics, 1977. I am not a professional astronomer but nonetheless, what I tell you is "Veritas".
In Feb. 2007 I discovered (eventually, on all of the four existing relevant online Red and Optical Infrared sky surveys) a body near the longitude predicted by David Todd, Percival Lowell, and Robert Harrington. It is near the positive CMB dipole, suggesting an alternative explanation for the correlation of the CMB multipoles with the ecliptic. Even without correction for Earth parallax, the coplanarity and constancy of angular speed are statistically significant. Its Red and Optical Infrared magnitudes are ~ +18.5. The images show the "Eberhard effect" characteristic of real stellar images on photographic emulsions.
This is really Lowell's "Planet X". Not receiving any reply from the International Astronomical Union, I named the planet myself: Barbarossa, after the legendary sleeping crusader.
My orbit fitting gives a=384 AU, e=0.61, and P=6340 +/- 7 yr. For a mass ~0.01 solar, there is a "precession resonance" with Neptune, Pluto, and the classical Kuiper Belt: the precession period of these orbits due to the average torque exerted by Barbarossa, is 3x, 2x, or 1x the precession period of these orbits due to the torque exerted by the known planets. Goldreich's nonexistence proof is faulty.
For many pulsars, Pdot/P clusters near small multiples of H0. This shows that there is something we do not understand about distant radio signals, from pulsars in particular. The alleged lack of acceleration toward pulsars, also is a faulty nonexistence proof.
Two stars with exceptionally strong "interstellar absorption", 61 Leonis and Theta Crateris, lie behind Barbarossa. My tabulation showed that there is a statistically significant excess of discordant Red and Blue USNO-B catalog magnitudes in this region. Barbarossa has a nebula that moves with it.
The correct interpretation of the "Sothic" date of Amenhotep I, is that it really refers to a heliacal rising of Arcturus, and occurs in an Egyptian calendar beginning at the summer solstice, 4328 BC. This gives 6339.5 tropical yr between the beginning of the lost Egyptian calendar, and the end of the Mayan Long Count. With only ~5% error, sqrt(kT/m) = H0*c*P, where P is the period of Barbarossa, H0 the Hubble parameter as now measured, T the CMB temperature, and m the mass of the proton (or hydrogen atom). My literature search found that according to the present state of the art, almost no dogmatic statements can be made about the diameter, albedo, or surface temperature of Barbarossa, a partially gravitationally collapsed body of unknown composition and origin.
I would be happy to meet with any or all faculty members of the University of ***** Astronomy Dept. in October for discussion. It is convenient for me to visit ***** then, because *********.
Sincerely,
Joseph C. Keller, M. D.
... POB 9122, Ames, Iowa 50014
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14 years 1 month ago #24003
by nemesis
Replied by nemesis on topic Reply from
I would have recommended you stop with the "two stars" paragraph, Joe. Most astronomers aren't likely to see what ancient Egyptian and Mayan calendars have to do with an unknown planet far beyond naked eye visibility, and it may raise a red flag. But, good luck.
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14 years 1 month ago #24004
by Jim
Replied by Jim on topic Reply from
nemesis, The bone of contention at this thread is more involved than your post indicates.
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