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Deep-Gas, Deep Hot Biosphere Theory
17 years 1 week ago #18198
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />Is this what your carbon atom would look like? It looks pretty, we could always sell them as a toy building set [][8D]
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
No.
Two protons coming together, tip to tip, would represent molecular hydrogen. They are pushed together because each proton is shielding the other proton from the gravitational flux. Almost any disturbance would break this connect - like a slight rise in temperature.
Two protons coming together, base to base, would be conventional nuclear fusion - a very rare event. If this fusion is achieved, it is deuterium. The deuterium assembly would have no lowest elevation point at which liquid Elysium would be trapped and then re-vaporized by the gravitons. However, it could readily form chemical bonds.
Protons coming together, side to side, would not happen. Deuterium could come together, side to side, because deuterium nuclei would not exhibit a re-vaporization of liquid Elysium - the "Coulomb repulsion". Under great pressure, within liquid Elysium, the deuterium nuclei would fuse together, side to side, creating a "random" polymer. This construct would grow until either the deuterium or the liquid Elysium has been exhausted - within the star at that particular location. Visualize sunspot.
One could not <b>build</b> a carbon nucleus. Its creation would come from radioactive decay of the "sunspot". The birth of carbon would be accidental, random.
Your pictured construct is impossible. It would fall apart instantly.
Gregg Wilson
<br />Is this what your carbon atom would look like? It looks pretty, we could always sell them as a toy building set [][8D]
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
No.
Two protons coming together, tip to tip, would represent molecular hydrogen. They are pushed together because each proton is shielding the other proton from the gravitational flux. Almost any disturbance would break this connect - like a slight rise in temperature.
Two protons coming together, base to base, would be conventional nuclear fusion - a very rare event. If this fusion is achieved, it is deuterium. The deuterium assembly would have no lowest elevation point at which liquid Elysium would be trapped and then re-vaporized by the gravitons. However, it could readily form chemical bonds.
Protons coming together, side to side, would not happen. Deuterium could come together, side to side, because deuterium nuclei would not exhibit a re-vaporization of liquid Elysium - the "Coulomb repulsion". Under great pressure, within liquid Elysium, the deuterium nuclei would fuse together, side to side, creating a "random" polymer. This construct would grow until either the deuterium or the liquid Elysium has been exhausted - within the star at that particular location. Visualize sunspot.
One could not <b>build</b> a carbon nucleus. Its creation would come from radioactive decay of the "sunspot". The birth of carbon would be accidental, random.
Your pictured construct is impossible. It would fall apart instantly.
Gregg Wilson
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17 years 1 week ago #18220
by Stoat
Replied by Stoat on topic Reply from Robert Turner
I'm not with you Gregg. Let's say we're talking about the decay of Hahnium; though there is evidence for heavier stable elements. One hundred and five protons, and one hundred and fifty five neutrons have to fit into the nucleus. the diameter of the nucleus doesn't vary by much over the periodic table. This calls for close order packing. Fission of this element isn't some sort of random explosion. The new lighter particles will have to close pack, have an internal order to them. That's why I thought you wanted a four sided pyramid, to allow for packing of units into the optimum volume.
Can you post a drawing of how you see these element fragments? I'm sure you know that I'm not keen on the whole idea but there are people here who seem eager to explore the idea.
Can you post a drawing of how you see these element fragments? I'm sure you know that I'm not keen on the whole idea but there are people here who seem eager to explore the idea.
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17 years 1 week ago #18221
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />I'm not with you Gregg.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I apologize. I have thought this a hundred times over the past 3 years, so it has become obvious to me. I starting to realize it is not obvious to other persons. What's the matter, guys, can't you read my mind?
In the beginning.. a vast nebula contains not just open (naked) protons but also elysons. Both "mediums" contract under gravitational flux (pressure) because the protons are <b>literally in the way.</b>
They have literally been forced "into a corner" because the gravitational flux comes from all directions. Because they shield one another, they collect together.
The contracting nebula heats up by the comventional Newtonian analysis. Compress a gas and get a higher temperature - which means a higher velocity for the protons and the elysons.
If two protons collide side to side, or tip to side, etc, it is a hard collision and they bounce apart. Keep in mind that I have given the proton a shape such that there is a "bottom of the well" for each proton. Any Elysium, which piles up on the protons surfaces, will flow - as a liquid from everywhere to the bottom of the inside of the pyramid (or cone, etc). Once any liquid Elysium reaches this lowest gravitational point on the proton, it can flow "downward" no farther. But it is still exposed to the gravitational flux. The gravitons re-vaporize this Elysium at the "bottom of the well" and it goes outward as a forceful, expanding vapor. This is the "Coulomb Repulsive Force". This action keeps much of the Elysium in a vapor state. Liquid Elysium cannot accumulate.
Once in a while (one out of a trillion collisions) two protons will approach one another, base to base. Since each of then is continuously giving off expanding vapor - think rocketship - the two expanding vapor "plumes" will mutually cancel each other out. The protons will connect, base to base, at essentially no velocity. It is a soft dock. Whatever Elysium was still "inside" the hollow pyramids becomes trapped. The clincher for holding the two protons together is that the gravitational flux (force) is on the outside but not on the inside of the mated protons.
We now have deuterium. It has no "bottom of the well" so there is no lowest point for liquid Elysium to flow to and then be vaporized from. The deuterium nuclei will ever so slowly collect together because they do not possess a "Coulomb Repulsive Force". The Elysium among them now has a region to "hide in" as a liquid (admittedly very hot by our standards). This is a mutual "condensation" by the deuterium nuclei and the elysons. Under great pressure but very little relative velocity, the deuterium will come together, <b>side to side</b>. <b>There is no alternative</b>. How compact the random polymer will become depends on pressure versus temperature.
Look very carefully at a large photograph of a sunspot.
Within this polymer (do not think straight chain!) there will be some voids. It will vary randomly. Eventually one has a monstrous nuclear mass. Because of its position, orbital velocity and mass, it will maintain an orbit while the remaining star material collapses inward. Once it is clear of the active star material, it is a newborn planet.
Any remaining, liquid Elysium will drain inward within the planet. Once the surface is no longer "protected" by liquid Elysium, it will be subject to standard nuclear collisions. This will initiate standard radioactive decay <b>on the surface</b>. As the pieces "fall off" the elements you are aware of in the Periodic Table, will come into existence. Pieces will decay until the fragment has enough open protons to create the "Coulomb Repulsive Force". Once that is achieved, you have a stable element.
So nuclear fusion is done at extremely low, relative velocities. Nuclear fission results from high, relative velocities.
Now show me where the Rubber Room is....
Gregg Wilson
<br />I'm not with you Gregg.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
I apologize. I have thought this a hundred times over the past 3 years, so it has become obvious to me. I starting to realize it is not obvious to other persons. What's the matter, guys, can't you read my mind?
In the beginning.. a vast nebula contains not just open (naked) protons but also elysons. Both "mediums" contract under gravitational flux (pressure) because the protons are <b>literally in the way.</b>
They have literally been forced "into a corner" because the gravitational flux comes from all directions. Because they shield one another, they collect together.
The contracting nebula heats up by the comventional Newtonian analysis. Compress a gas and get a higher temperature - which means a higher velocity for the protons and the elysons.
If two protons collide side to side, or tip to side, etc, it is a hard collision and they bounce apart. Keep in mind that I have given the proton a shape such that there is a "bottom of the well" for each proton. Any Elysium, which piles up on the protons surfaces, will flow - as a liquid from everywhere to the bottom of the inside of the pyramid (or cone, etc). Once any liquid Elysium reaches this lowest gravitational point on the proton, it can flow "downward" no farther. But it is still exposed to the gravitational flux. The gravitons re-vaporize this Elysium at the "bottom of the well" and it goes outward as a forceful, expanding vapor. This is the "Coulomb Repulsive Force". This action keeps much of the Elysium in a vapor state. Liquid Elysium cannot accumulate.
Once in a while (one out of a trillion collisions) two protons will approach one another, base to base. Since each of then is continuously giving off expanding vapor - think rocketship - the two expanding vapor "plumes" will mutually cancel each other out. The protons will connect, base to base, at essentially no velocity. It is a soft dock. Whatever Elysium was still "inside" the hollow pyramids becomes trapped. The clincher for holding the two protons together is that the gravitational flux (force) is on the outside but not on the inside of the mated protons.
We now have deuterium. It has no "bottom of the well" so there is no lowest point for liquid Elysium to flow to and then be vaporized from. The deuterium nuclei will ever so slowly collect together because they do not possess a "Coulomb Repulsive Force". The Elysium among them now has a region to "hide in" as a liquid (admittedly very hot by our standards). This is a mutual "condensation" by the deuterium nuclei and the elysons. Under great pressure but very little relative velocity, the deuterium will come together, <b>side to side</b>. <b>There is no alternative</b>. How compact the random polymer will become depends on pressure versus temperature.
Look very carefully at a large photograph of a sunspot.
Within this polymer (do not think straight chain!) there will be some voids. It will vary randomly. Eventually one has a monstrous nuclear mass. Because of its position, orbital velocity and mass, it will maintain an orbit while the remaining star material collapses inward. Once it is clear of the active star material, it is a newborn planet.
Any remaining, liquid Elysium will drain inward within the planet. Once the surface is no longer "protected" by liquid Elysium, it will be subject to standard nuclear collisions. This will initiate standard radioactive decay <b>on the surface</b>. As the pieces "fall off" the elements you are aware of in the Periodic Table, will come into existence. Pieces will decay until the fragment has enough open protons to create the "Coulomb Repulsive Force". Once that is achieved, you have a stable element.
So nuclear fusion is done at extremely low, relative velocities. Nuclear fission results from high, relative velocities.
Now show me where the Rubber Room is....
Gregg Wilson
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17 years 1 week ago #18226
by Stoat
Replied by Stoat on topic Reply from Robert Turner
If you take three quarks and add a fourth nodal point for their centre of gravity, then connect them all together with Le Sage shadows, we would have a tetrahedron. The shadows, being of lower spatial density, pull the quarks in the "space" of the particles pushes them back out. Now spin this whole thing like a little gyroscope and you have a little shadow cone. The "walls" are constructed from a medium which can have incredible tensional and compressionable strength. The aether makes steel look like candy floss by comparison.
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17 years 6 days ago #18231
by Gregg
Replied by Gregg on topic Reply from Gregg Wilson
<blockquote id="quote"><font size="2" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by Stoat</i>
<br />If you take three quarks and add a fourth nodal point for their centre of gravity, then connect them all together with Le Sage shadows, we would have a tetrahedron. The shadows, being of lower spatial density, pull the quarks in the "space" of the particles pushes them back out. Now spin this whole thing like a little gyroscope and you have a little shadow cone. The "walls" are constructed from a medium which can have incredible tensional and compressionable strength. The aether makes steel look like candy floss by comparison.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
"Yes...yes..yes.." said Alice, "But did you see which way the White Rabbit went?"
Gregg Wilson
<br />If you take three quarks and add a fourth nodal point for their centre of gravity, then connect them all together with Le Sage shadows, we would have a tetrahedron. The shadows, being of lower spatial density, pull the quarks in the "space" of the particles pushes them back out. Now spin this whole thing like a little gyroscope and you have a little shadow cone. The "walls" are constructed from a medium which can have incredible tensional and compressionable strength. The aether makes steel look like candy floss by comparison.
<hr height="1" noshade id="quote"></blockquote id="quote"></font id="quote">
"Yes...yes..yes.." said Alice, "But did you see which way the White Rabbit went?"
Gregg Wilson
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- Larry Burford
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17 years 6 days ago #18232
by Larry Burford
Replied by Larry Burford on topic Reply from Larry Burford
The aether makes candy floss look like steel by comparison.
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